Wavelet regression/correlation for Kelvin wave ...

  1. At equivalent depth 200 m, the wave is not well repsresented, see the script that I wrote. becuase I am very near to period of the 2*dt. The solution to this problem is to increase the resoltuion, np.arange(1,100,0.5). But this means that I need more higher resoltuion data to work. I am currelnly working on daily data np.arange(100). If I have data every 12 hours, then I can say np.arange(1,100,0.5). For daily data, this is our limit at 200 and I think that it is less than 200, may be 100. You must take a look at the wavelet shape before using it.
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